Question

How to check whether a matrix is a magic square or not in Kotlin

Answer 1

object MagicSquareChecker {

    // Function to check if the matrix is a magic square
    fun isMagicSquare(matrix: Array<IntArray>): Boolean {
        val size = matrix.size
        var sumDiagonal1 = 0
        var sumDiagonal2 = 0

        // Calculate the sum of the primary diagonal
        for (i in 0 until size) {
            sumDiagonal1 += matrix[i][i]
        }

        // Calculate the sum of the secondary diagonal
        for (i in 0 until size) {
            sumDiagonal2 += matrix[i][size - i - 1]
        }

        // If the two diagonals don't have the same sum, it's not a magic square
        if (sumDiagonal1 != sumDiagonal2) {
            return false
        }

        // Check sums of each row and column
        for (i in 0 until size) {
            var sumRow = 0
            var sumCol = 0

            for (j in 0 until size) {
                sumRow += matrix[i][j]  // Sum of the current row
                sumCol += matrix[j][i]  // Sum of the current column
            }

            // If any row or column sum is not equal to the diagonal sum, it's not a magic square
            if (sumRow != sumDiagonal1 || sumCol != sumDiagonal1) {
                return false
            }
        }

        // If all checks pass, it's a magic square
        return true
    }

    @JvmStatic
    fun main(args: Array<String>) {
        val matrix = arrayOf(
            intArrayOf(8, 3, 4),
            intArrayOf(1, 5, 9),
            intArrayOf(6, 7, 2)
        )

        if (isMagicSquare(matrix)) {
            println("The given matrix is a magic square.")
        } else {
            println("The given matrix is NOT a magic square.")
        }
    }
}


/*
run:

The given matrix is a magic square.

*/

 

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