"""
next_multiple_of_10:
--------------------
Returns the next multiple of 10 greater than or equal to n.
Algorithm:
- Add 9 to n: this ensures that any number not already a multiple of 10
will "spill over" into the next multiple when integer-divided by 10.
- Divide by 10: integer division truncates toward zero.
- Multiply by 10: reconstruct the multiple of 10.
Example:
n = 23 → (23 + 9) = 32 → 32 / 10 = 3 → 3 * 10 = 30
n = 40 → (40 + 9) = 49 → 49 / 10 = 4 → 4 * 10 = 40
"""
def next_multiple_of_10(n):
return ((n + 9) // 10) * 10
"""
main:
-----
Demonstrates the function with a sample input.
"""
def main():
nums = [23, 10, 0, 1, 1841]
length = len(nums)
for i in range(length):
print(next_multiple_of_10(nums[i]))
main()
"""
run:
30
10
0
10
1850
"""
