How to check whether a number is positive/zero/negative without using conditional statements in Pascal

1 Answer

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program SignCheck;

{$APPTYPE CONSOLE}

var
  n: Integer;
  index: Integer;
  resultLabels: array[0..2] of PChar;

begin
  n := 89;

  // create text labels for each possible case
  resultLabels[0] := 'negative';  // index 0
  resultLabels[1] := 'zero';      // index 1
  resultLabels[2] := 'positive';  // index 2

  // compute an index without using any conditional statements
  // (n > 0) becomes 1 if true, 0 if false
  // (n < 0) becomes 1 if true, 0 if false
  // index = 1 + (n > 0) - (n < 0)
  index := 1 + Ord(n > 0) - Ord(n < 0);

  // print the classification
  Writeln(resultLabels[index]);

  (*
       Checks:

       n = -3
       (n > 0) = 0
       (n < 0) = 1
       index = 1 + 0 - 1 = 0
       result = negative

       n = 0
       (n > 0) = 0
       (n < 0) = 0
       index = 1 + 0 - 0 = 1
       result = zero

       n = 89
       (n > 0) = 1
       (n < 0) = 0
       index = 1 + 1 - 0 = 2
       result = positive
  *)

end.


(*
run:

positive

*)

 



answered Jun 27 by avibootz

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