How to calculate the 100th term of the sequence 8, 64, 80, 136, 152 in Python

1 Answer

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"""
 
Pattern Explanation:
 
The sequence is: 8, 64, 80, 136, 152
 
Compute the differences between consecutive numbers:
64  - 8   = 56
80  - 64  = 16
136 - 80  = 56
152 - 136 = 16
 
The pattern clearly alternates:
+56, +16, +56, +16, ...
 
8   + 56 =  64
64  + 16 =  80
80  + 56 = 136
136 + 16 = 152
 
This alternating pattern continues forever.
 
Even-term formula:
Term(2) = 64
Each pair adds: 56 + 16 = 72
 
Number of even terms up to Term(100):
100 / 2 = 50 even terms
 
Number of full pairs after Term(2):
50 - 1 = 49 pairs
 
Formula for even terms:
Term(n) = 64 + 72 × (n/2 - 1)
 
For n = 100:
Term(100) = 64 + 72 × 49 = 3592
 
"""

# ------------------------------------------------------------
# Function to compute the nth term using the even-term formula
# ------------------------------------------------------------
def nth_term(n: int) -> int:
    if n == 1:
        return 8  # first term is fixed

    if n % 2 == 0:
        # Even term formula
        return 64 + 72 * (n // 2 - 1)
    else:
        # Odd term = previous even term + 16
        even_term = 64 + 72 * ((n - 1) // 2 - 1)
        return even_term + 16


def main():
    n = 100
    result = nth_term(n)
    print(f"The 100th term of the sequence is: {result}")


if __name__ == "__main__":
    main()


"""
Run:
 
The 100th term of the sequence is: 3592
 
"""

 



answered 1 day ago by avibootz

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