How to calculate the 100th term of the sequence 8, 64, 80, 136, 152 in VB.NET

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Imports System

'Pattern Explanation:
'
'The sequence is: 8, 64, 80, 136, 152
'
'Compute the differences between consecutive numbers:
'64  - 8   = 56
'80  - 64  = 16
'136 - 80  = 56
'152 - 136 = 16
'
'The pattern clearly alternates:
'+56, +16, +56, +16, ...
'
'8   + 56 =  64
'64  + 16 =  80
'80  + 56 = 136
'136 + 16 = 152
'
'This alternating pattern continues forever.
'
'Even-term formula:
'Term(2) = 64
'Each pair adds: 56 + 16 = 72
'
'Number of even terms up to Term(100):
'100 / 2 = 50 even terms
'
'Number of full pairs after Term(2):
'50 - 1 = 49 pairs
'
'Formula for even terms:
'Term(n) = 64 + 72 × (n/2 - 1)
'
'For n = 100:
'Term(100) = 64 + 72 × 49 = 3592
'


Module NextSequenceNumber

    ' ------------------------------------------------------------
    ' Function to compute the nth term using the even-term formula
    ' ------------------------------------------------------------
    Function NthTerm(n As Integer) As Integer
        If n = 1 Then
            Return 8   ' first term is fixed
        End If

        If n Mod 2 = 0 Then
            ' Even term formula
            Return 64 + 72 * (n \ 2 - 1)
        Else
            ' Odd term = previous even term + 16
            Dim evenTerm As Integer = 64 + 72 * ((n - 1) \ 2 - 1)
            Return evenTerm + 16
        End If
    End Function

    Sub Main()
        Dim n As Integer = 100

        Dim resultValue As Integer = NthTerm(n)

        Console.WriteLine("The 100th term of the sequence is: " & resultValue)
    End Sub

End Module



' Run:
'
' The 100th term of the sequence is: 3592
'


 



answered May 12 by avibootz

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