How to produce a sequential count in octal, starting at zero in C#

1 Answer

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// Fixed‑width octal (e.g., always 3 digits)

using System;

class Program
{
    static void Main()
    {
        for (int i = 0; i < 65; i++) {
            string octal = Convert.ToString(i, 8).PadLeft(3, '0');
            Console.WriteLine(i + " = " + octal);
        }
    }
}


/*
run:

0 = 000
1 = 001
2 = 002
3 = 003
4 = 004
5 = 005
6 = 006
7 = 007
8 = 010
9 = 011
10 = 012
11 = 013
12 = 014
13 = 015
14 = 016
15 = 017
16 = 020
17 = 021
18 = 022
19 = 023
20 = 024
21 = 025
22 = 026
23 = 027
24 = 030
25 = 031
26 = 032
27 = 033
28 = 034
29 = 035
30 = 036
31 = 037
32 = 040
33 = 041
34 = 042
35 = 043
36 = 044
37 = 045
38 = 046
39 = 047
40 = 050
41 = 051
42 = 052
43 = 053
44 = 054
45 = 055
46 = 056
47 = 057
48 = 060
49 = 061
50 = 062
51 = 063
52 = 064
53 = 065
54 = 066
55 = 067
56 = 070
57 = 071
58 = 072
59 = 073
60 = 074
61 = 075
62 = 076
63 = 077
64 = 100

*/

 



answered Mar 24 by avibootz
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