How to remove the last n occurrences of a substring in a string in Kotlin

1 Answer

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// Remove last n occurrences of a substring
fun removeLastNOccurrences(s: String, sub: String, n: Int): String {
    val positions = mutableListOf<Int>()
    var pos = s.indexOf(sub)
    var offset: Int

    // Find all occurrences
    while (pos != -1) {
        positions += pos
        offset = pos + sub.length
        pos = s.indexOf(sub, offset)
    }

    // Remove from the end
    var result = s
    var remaining = n

    for (start in positions.asReversed()) {
        if (remaining == 0) break
        result = result.removeRange(start, start + sub.length)
        remaining--
    }

    return result
}

// Remove extra spaces (collapse multiple spaces, trim ends)
fun removeExtraSpaces(s: String): String =
    s.trim().split(Regex("\\s+")).joinToString(" ")

fun main() {
    val text = "abc xyz xyz abc xyzabcxyz abc"

    val result = removeLastNOccurrences(text, "xyz", 3)
    println(result)

    val cleaned = removeExtraSpaces(result)
    println(cleaned)
}



/*
run:

abc xyz  abc abc abc
abc xyz abc abc abc

*/




answered Feb 16 by avibootz

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