Question

How to caculate the harmonic series Hn = 1 + 1/2 + 1/3 + 1/4 + 1/n in C

Answer 1

#include <stdio.h>

double harmonic(int n) {
    double sum = 0.0;

    for (int i = 1; i <= n; i++) {
        sum += 1.0 / i;   // add 1/i as double
    }

    return sum;
}

int main(void) {
    int n = 5;

    printf("H_%d = %.5f\n", n, harmonic(n));

    return 0;
}


/*
run:

H_5 = 2.28333

*/

 

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