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How to find two prime numbers that, when concatenated, form another prime number in C++

1 Answer

0 votes
#include <iostream>
#include <vector>

// Function to check primality
bool isPrime(long long n) {
    if (n < 2) return false;
    if (n % 2 == 0 && n != 2) return false;
    
    for (long long i = 3; i * i <= n; i += 2) {
        if (n % i == 0) return false;
    }
    
    return true;
}

// Concatenate two integers
long long concat(int a, int b) {
    std::string s = std::to_string(a) + std::to_string(b);
    
    return stoll(s);
}

int main() {
    // Generate primes up to a limit
    int limit = 12; // you can increase this
    std::vector<int> primes;
    
    for (int i = 2; i <= limit; i++) {
        if (isPrime(i)) primes.push_back(i);
    }

    // Check pairs
    for (int i = 0; i < primes.size(); i++) {
        for (int j = 0; j < primes.size(); j++) {
            if (i == j) continue; // skip same prime if you want
            long long num = concat(primes[i], primes[j]);
            if (isPrime(num)) {
                std::cout << primes[i] << " + " << primes[j]
                          << " -> " << num << " is prime\n";
            }
        }
    }
}



/*
run:

2 + 3 -> 23 is prime
2 + 11 -> 211 is prime
3 + 7 -> 37 is prime
3 + 11 -> 311 is prime
5 + 3 -> 53 is prime
7 + 3 -> 73 is prime
11 + 3 -> 113 is prime

*/

 



answered Nov 28, 2025 by avibootz
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