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How to replace a digit in a floating-point number by index with Scala

1 Answer

0 votes
object ReplaceFloatDigitDemo {

  /**
   * Replace a digit at a given position in a floating-point number.
   */
  def replaceFloatDigit(number: Double, position: Int, newDigit: Char): Double = {
    // Validate that newDigit is indeed a single digit
    if (!newDigit.isDigit) {
      throw new IllegalArgumentException("Replacement must be a digit (0-9).")
    }

    // Convert number to string with fixed precision (10 decimal places)
    val strNum = f"$number%.10f"

    // Validate position
    if (position < 0 || position >= strNum.length) {
      throw new IndexOutOfBoundsException("Position is out of range for the number string.")
    }

    // Ensure position points to a digit
    if (strNum(position) == '.' || strNum(position) == '-') {
      throw new IllegalArgumentException("Position points to a non-digit character.")
    }

    // Replace digit (strings are immutable, so build a new one)
    val modified = strNum.updated(position, newDigit)

    // Convert back to Double
    modified.toDouble
  }

  def main(args: Array[String]): Unit = {
    try {
      val num = 89710.291
      val pos = 2        // 0-based index
      val newDigit = '8'

      val result = replaceFloatDigit(num, pos, newDigit)
      // Print result with 3 decimal places
      println(f"Modified number: $result%.3f")
    } catch {
      case e: Exception =>
        Console.err.println(s"Error: ${e.getMessage}")
    }
  }
}




/*
run:

Modified number: 89810.291

*/

 



answered Nov 17, 2025 by avibootz
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