Question

How to create and initialize a sequence in Scala

Answer 1

object SeqCreateAndInitialize   {
  def main(args: Array[String]): Unit = {
    // Create an immutable sequence
    val seq = Seq(1, 2, 3, 4)

    // 1. Print the whole sequence directly
    println(seq) 

    // 2. Print elements separated by spaces
    println(seq.mkString(" "))

    // 3. Print elements with custom formatting
    println(seq.mkString("[", ", ", "]")) 

    // 4. Iterate and print each element
    seq.foreach(println)
  }
}



/*
run:

List(1, 2, 3, 4)
1 2 3 4
[1, 2, 3, 4]
1
2
3
4

*/

 

70+ SQL courses for beginners and professionals

Answer 2

object SeqCreateAndInitialize   {
  def main(args: Array[String]): Unit = {
    // Creates a sequence with n copies of a given value
    val filledSeq = Seq.fill(3)("Scala")

    // 1. Print the whole sequence directly
    println(filledSeq) 

    // 2. Print elements separated by spaces
    println(filledSeq.mkString(" "))

    // 3. Print elements with custom formatting
    println(filledSeq.mkString("[", ", ", "]")) 

    // 4. Iterate and print each element
    filledSeq.foreach(println)
  }
}



/*
run:

List(Scala, Scala, Scala)
Scala Scala Scala
[Scala, Scala, Scala]
Scala
Scala
Scala

*/

 

70+ SQL courses for beginners and professionals

Answer 3

object SeqCreateAndInitialize   {
  def main(args: Array[String]): Unit = {
    // Creates a sequence of numbers within a range.
    val rangeSeq = Seq.range(1, 10, 2) // List(1, 3, 5, 7, 9)

    // 1. Print the whole sequence directly
    println(rangeSeq) 

    // 2. Print elements separated by spaces
    println(rangeSeq.mkString(" "))

    // 3. Print elements with custom formatting
    println(rangeSeq.mkString("[", ", ", "]")) 

    // 4. Iterate and print each element
    rangeSeq.foreach(println)
  }
}



/*
run:

NumericRange 1 until 10 by 2
1 3 5 7 9
[1, 3, 5, 7, 9]
1
3
5
7
9

*/

 

70+ SQL courses for beginners and professionals