How to check if two strings are anagram (same letters different words) in Swift

1 Answer

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import Foundation

func areAnagram(_ s1: String, _ s2: String) -> Bool {
    guard s1.count == s2.count else { return false }

    var freq: [Character: Int] = [:]

    for ch in s1 {
        freq[ch, default: 0] += 1
    }

    for ch in s2 {
        guard let count = freq[ch] else { return false }
        if count == 1 {
            freq.removeValue(forKey: ch)
        } else {
            freq[ch] = count - 1
        }
    }

    return freq.isEmpty
}

print(areAnagram("swift", "wifts") ? "yes" : "no")
print(areAnagram("swift", "twisf") ? "yes" : "no")
print(areAnagram("swift", "swifi") ? "yes" : "no")



/*
run:

yes
yes
no

*/

 



answered Nov 13, 2025 by avibootz
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