How to find all the numbers that are equal to the sum of the factorials of their digits in Kotlin

1 Answer

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// Example: 145 = 1! + 4! + 5! = 1 + 24 + 120 = 145

// Function to compute the factorial of a number
fun factorial(n: Int): Int {
    var fact = 1
    
    for (i in 2..n) {
        fact *= i
    }
    
    return fact
}

// Function to find all numbers equal to the sum of the factorials of their digits
fun findDigitFactorialNumbers() {
    // Precompute factorials of digits 0–9
    val factorials = IntArray(10) { factorial(it) }

    // Define an upper limit (7 * 9! is a safe limit for this problem)
    val upperLimit = 7 * factorials[9]

    // Iterate through all numbers and check the condition
    for (num in 10..upperLimit) {
        var sum = 0
        var temp = num

        // Calculate the sum of factorials of digits
        while (temp > 0) {
            val digit = temp % 10
            sum += factorials[digit]
            temp /= 10
        }

        // Check if the number equals the sum of the factorials of its digits
        if (sum == num) {
            println("$num is a digit factorial number.")
        }
    }
}

fun main() {
    findDigitFactorialNumbers()
}



/*
run:

145 is a digit factorial number.
40585 is a digit factorial number.

*/

 



answered Nov 10, 2025 by avibootz
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