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How to swap all odd and even bits in VB.NET

1 Answer

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Imports System

Module BitManipulation

    ' Prints the 8-bit binary representation of a number.
    Sub PrintBinary(value As Long)
        Console.WriteLine(Convert.ToString(value And &HFF, 2).PadLeft(8, "0"c))
    End Sub

    ' Swaps odd and even bits in a 32-bit integer.
    Function SwapOddAndEvenBits(n As Integer) As Long
        ' (binary: 101010...) to isolate odd bits.
        Dim oddBits As Long = n And &HAAAAAAAA

        ' (binary: 010101...) to isolate even bits.
        Dim evenBits As Long = n And &H55555555

        Console.Write("oddBits:  ")
        PrintBinary(oddBits)

        Console.Write("evenBits: ")
        PrintBinary(evenBits)

        ' Right-shift odd bits by 1 to move them to even positions.
        oddBits >>= 1

        ' Left-shift even bits by 1 to move them to odd positions.
        evenBits <<= 1

        Console.Write("oddBits Right-shift: ")
        PrintBinary(oddBits)

        Console.Write("evenBits Left-shift: ")
        PrintBinary(evenBits)

        ' Combine shifted bits
        Return oddBits Or evenBits
    End Function

    Sub Main()
        Dim n As Integer = 90

        ' Original number in binary
        PrintBinary(n)

        Dim result As Long = SwapOddAndEvenBits(n)

        ' Final result in binary
        PrintBinary(result)
    End Sub

End Module



' run:
'
' 01011010
' oddBits:  00001010
' evenBits: 01010000
' oddBits Right-shift: 00000101
' evenBits Left-shift: 10100000
' 10100101
'

 



answered Oct 25, 2025 by avibootz

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