Question

How to generate a random hexadecimal string in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void generateHex(char *hexStr, int length) {
    const char hexChars[] = "0123456789ABCDEF";

    for (int i = 0; i < length; ++i) {
        hexStr[i] = hexChars[rand() % 16];
    }
    hexStr[length] = '\0'; // Null-terminate the string
}

int main() {
    srand((unsigned int)time(NULL)); // Seed the random number generator

    int length = 8;
    char hexNumber[9]; // 8 characters + null terminator

    generateHex(hexNumber, length);

    printf("Random Hexadecimal Number: %s\n", hexNumber);

    return 0;
}



/*
run:

Random Hexadecimal Number: 3E275186

*/

 

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