How to sort an array that consists of only 0s and 1s in Java

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public class SortBinaryArray {

    // Function to sort an array containing only 0s and 1s
    public static void sortBinaryArray(int[] arr) {
        int left = 0;                  // Index to track the left side
        int right = arr.length - 1;    // Index to track the right side

        while (left < right) {
            // If the left index is at 0, move it forward
            if (arr[left] == 0) {
                System.out.println("left: " + left);
                left++;
            }
            // If the right index is at 1, move it backward
            else if (arr[right] == 1) {
                System.out.println("right: " + right);
                right--;
            }
            // If left is 1 and right is 0, swap them
            else {
                int temp = arr[left];
                arr[left] = arr[right];
                arr[right] = temp;
                System.out.println("swap() left: " + left + " right: " + right);
                left++;
                right--;
            }
        }
    }

    public static void main(String[] args) {
        // Input: Binary array
        int[] arr = {1, 0, 1, 0, 1, 0, 0, 1, 0};

        // Sort the binary array
        sortBinaryArray(arr);

        // Output the sorted array
        System.out.print("Sorted array: ");
        for (int num : arr) {
            System.out.print(num + " ");
        }
    }
}



/*
run:

swap() left: 0 right: 8
left: 1
right: 7
swap() left: 2 right: 6
left: 3
swap() left: 4 right: 5
Sorted array: 0 0 0 0 0 1 1 1 1 

*/


 



answered Sep 2, 2025 by avibootz
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