Question

How to convert an integer to a string in base b with Go

Answer 1

package main

import (
	"fmt"
	"strconv"
	"strings"
)

func main() {
	num := 255
	base := 16

	// Convert to string in base 2 (binary)
	binaryStr := strconv.FormatInt(int64(num), 2)
	fmt.Println("Binary:", binaryStr)

	// Convert to string in base 16 (hexadecimal)
	hexStr := strings.ToUpper(strconv.FormatInt(int64(num), base))
	fmt.Println("Hexadecimal:", hexStr)

	// Convert to string in base 8 (octal)
	octalStr := strconv.FormatInt(int64(num), 8)
	fmt.Println("Octal:", octalStr)
}



/*
run:

Binary: 11111111
Hexadecimal: FF
Octal: 377

*/

 

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