Question

How to sum the proper divisors of a number in Swift

Answer 1

func sumNumberProperDivisors(_ num: Int) -> Int {
    var sum = 0

    for i in 1...(num / 2) {
        if num % i == 0 {
            print("\(i), ", terminator: "")
            sum += i
        }
    }

    return sum
}

let sum = sumNumberProperDivisors(220)

print("\n\(sum)")



/*
run:

1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 
284

*/

 

70+ SQL courses for beginners and professionals