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How to deallocate a 2D array in C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h>

int main() {
    int rows = 3, cols = 4;

    // Dynamically allocate memory
    int** array = (int**)malloc(rows * sizeof(int*));
    if (array == NULL) {
        printf("Memory allocation failed for rows.\n");
        return 1;
    }

    for (int i = 0; i < rows; i++) {
        array[i] = (int*)malloc(cols * sizeof(int));
        if (array[i] == NULL) {
            printf("Memory allocation failed for row %d.\n", i);
            // Free previously allocated rows before exiting
            for (int j = 0; j < i; j++) {
                free(array[j]);
            }
            free(array);
            return 1;
        }
    }


    // Deallocate memory
    for (int i = 0; i < rows; i++) {
        free(array[i]); // Free each row
    }
    free(array); // Free the array of pointers

    return 0;
}

 
 
/*
run:
 


*/

 



answered Aug 8, 2025 by avibootz
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