Question

How to convert binary digits to a byte array in Swift

Answer 1

import Foundation

func binaryToByteArray(_ binaryString: String) throws -> [UInt8] {
    guard binaryString.count % 8 == 0 else {
        throw NSError(domain: "BinaryError", code: 1, userInfo: [NSLocalizedDescriptionKey: "Binary string length must be a multiple of 8."])
    }

    var byteArray: [UInt8] = []

    for i in stride(from: 0, to: binaryString.count, by: 8) {
        let startIndex = binaryString.index(binaryString.startIndex, offsetBy: i)
        let endIndex = binaryString.index(startIndex, offsetBy: 8)
        let byteString = String(binaryString[startIndex..<endIndex])
        if let byte = UInt8(byteString, radix: 2) {
            byteArray.append(byte)
        } else {
            throw NSError(domain: "ConversionError", code: 2, userInfo: [NSLocalizedDescriptionKey: "Invalid binary segment: \(byteString)"])
        }
    }

    return byteArray
}

let binaryString = "10101110111010101110101001001011"

do {
    let byteList = try binaryToByteArray(binaryString)
    print("Byte List:", byteList.map { String($0) }.joined(separator: " "))
} catch {
    print("Error: \(error.localizedDescription)")
}




/*
run:

Byte List: 174 234 234 75

*/

 

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