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How to convert binary digits to a byte sequence in Scala

1 Answer

0 votes
object BinaryConverter {

  def binaryToByteSequence(binaryString: String): Seq[Int] = {
    if (binaryString.length % 8 != 0)
      throw new IllegalArgumentException("Binary string length must be a multiple of 8.")

    (0 until binaryString.length by 8).map { i =>
      val byteSegment = binaryString.substring(i, i + 8)
      Integer.parseInt(byteSegment, 2)
    }
  }

  def main(args: Array[String]): Unit = {
    val binaryString = "10101110111010101110101001001011"

    try {
      val byteList = binaryToByteSequence(binaryString)
      println("Byte List: " + byteList.mkString(" "))
    } catch {
      case e: IllegalArgumentException =>
        Console.err.println(s"Error: ${e.getMessage}")
    }
  }
}



/*
run:
 
Byte List: 174 234 234 75
 
*/

 



answered Aug 4, 2025 by avibootz
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