Question

How to convert binary digits to a slice of bytes in Go

Answer 1

package main

import (
    "fmt"
    "strconv"
)

// binaryToByteArray converts a binary string to a slice of bytes
func binaryToByteArray(binaryString string) ([]byte, error) {
    if len(binaryString)%8 != 0 {
        return nil, fmt.Errorf("binary string length must be a multiple of 8")
    }

    var byteList []byte
    for i := 0; i < len(binaryString); i += 8 {
        byteSegment := binaryString[i : i+8]
        byteValue, err := strconv.ParseUint(byteSegment, 2, 8)
        if err != nil {
            return nil, fmt.Errorf("invalid binary segment: %s", byteSegment)
        }
        byteList = append(byteList, byte(byteValue))
    }

    return byteList, nil
}

func main() {
    binaryString := "10101110111010101110101001001011"

    byteList, err := binaryToByteArray(binaryString)
    if err != nil {
        fmt.Println("Error:", err)
        return
    }

    fmt.Print("Byte List: ")
    for _, b := range byteList {
        fmt.Printf("%d ", b)
    }
}



/*
run:

Byte List: 174 234 234 75 

*/

 

70+ SQL courses for beginners and professionals