Question

How to sum the digits of the number 2^N in TypeScript

Answer 1

function sumOfDigits(power: number): number {
    const num: BigInt = BigInt(2 ** power).toString(); // Handle large numbers
   
    return num.split('').reduce((sum, digit) => sum + Number(digit), 0);
}
 
console.log(sumOfDigits(15)); 
console.log(sumOfDigits(100)); 
console.log(sumOfDigits(1000)); 
 
 
 
/*
run:
 
26
115
1366
 
*/

 

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Answer 2

function sumOfDigits(power: number): number {
    const num: BigInt = BigInt(2 ** power).toString(); // Handle large numbers
   
    let sum: number = 0;
     
    for (let digit of num) {
        sum += Number(digit);
    }
     
    return sum;
}
 
console.log(sumOfDigits(15)); 
console.log(sumOfDigits(100)); 
console.log(sumOfDigits(1000)); 
 
 
 
/*
run:
 
26
115
1366
 
*/

 

70+ SQL courses for beginners and professionals

Answer 3

function sumOfDigits(power: number): number {
    const num: BigInt = BigInt(2 ** power).toString(); // Handle large numbers
   
   return Array.from(num).map(Number).reduce((sum, digit) => sum + digit, 0);
}
 
console.log(sumOfDigits(15)); 
console.log(sumOfDigits(100)); 
console.log(sumOfDigits(1000)); 
 
 
 
/*
run:
 
26
115
1366
 
*/

 

70+ SQL courses for beginners and professionals