Question

How to declare a function argument that can accept any type in Java

Answer 1

public class Program {
    public static <T> void AcceptAnyType(T x) {
        if (x instanceof String) {
            System.out.println("The argument is a String.");
        } else if (x instanceof Integer) {
            System.out.println("The argument is an Integer.");
        } else {
            System.out.println("The argument is of type: " + x.getClass().getName());
        }
    }
    public static void main(String[] args) {
        AcceptAnyType(384);      // Integer
        AcceptAnyType("ABCD");   // String
        AcceptAnyType(3.14);     // Double
    }
}



/*
run:

The argument is an Integer.
The argument is a String.
The argument is of type: java.lang.Double

*/

 

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Answer 2

public class Program {
    public static void AcceptAnyType(Object x) {
        if (x instanceof String) {
            System.out.println("The argument is a String.");
        } else if (x instanceof Integer) {
            System.out.println("The argument is an Integer.");
        } else {
            System.out.println("The argument is of type: " + x.getClass().getName());
        }
    }

    public static void main(String[] args) {
        AcceptAnyType(384);      // Integer
        AcceptAnyType("ABCD");   // String
        AcceptAnyType(3.14);     // Double
    }
}



/*
run:

The argument is an Integer.
The argument is a String.
The argument is of type: java.lang.Double

*/

 

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