Question

How to get the lower 8 bits of an int in Rust

Answer 1

fn print_binary(n: u16, width: usize) -> String {
    let binary = format!("{:b}", n);
    format!("{:0>width$}", binary, width = width)
}

fn main() {
    let n: u16 = 1957;

    // Print 16-bit binary of n
    println!("{}", print_binary(n, 16));

    // Extract low 8 bits and print
    let low8bits = n & 0xFF;
    println!("{}", print_binary(low8bits, 16)); // Also padded to 16 bits
}


    
/*
run:

0000011110100101
0000000010100101
   
*/

 

70+ SQL courses for beginners and professionals