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How to set specific bits in a char with Kotlin

1 Answer

0 votes
fun printBinary(ch: Int) {
    val binary = ch and 0xFF // Mask to 8 bits
    println(String.format("%8s", Integer.toBinaryString(binary)).replace(' ', '0'))
}

fun main() {
    var ch = 0
    ch = ch or (1 shl 7) // Set the 7th bit (128)
    ch = ch or (1 shl 3) // Set the 3rd bit (8)

    printBinary(ch)            // Binary representation: 10001000
    println("Value: $ch")      // Decimal value: 136
}

 
  
/*
run:
 
10001000
Value: 136

*/

 



answered Jul 31, 2025 by avibootz
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