Question

How to check if two integers have opposite signs in TypeScript

Answer 1

let x: number = 3, y: number = -9;            
let b: boolean = ((x ^ y) < 0); 
console.log(b);
       
x = 5, y = 6;
b = ((x ^ y) < 0); 
console.log(b);
       
  
     
/*
run:
      
true
false
       
*/

 

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