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How to extract a file name from a path, replace whitespaces, and make it lowercase using RegEx in Python

1 Answer

0 votes
import re

def normalize_filename(file_path: str) -> str:
    # Extract the file name using regex
    match = re.search(r'^.*[\\/](.*)$', file_path)
    filename = match.group(1) if match else file_path

    # Replace whitespaces with underscores
    filename = filename.replace(' ', '_')

    # Convert to lowercase
    filename = filename.lower()

    return filename

file_path = r"c:\path\to\file\WITH Whitespace1 and Whitespace2.py"

result = normalize_filename(file_path)

print(result)

 
 
'''
run:
 
with_whitespace1_and_whitespace2.py
 
'''

 



answered Jul 15, 2025 by avibootz
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