Question

How to filter an array in-place with Node.js

Answer 1

let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 14];
 
// Filter in-place to keep only even numbers
for (let i = array.length - 1; i >= 0; i--) {
    if (array[i] % 2 === 0) {
        array.splice(i, 1); // Remove the element if it doesn't meet the condition
    }
}
 
console.log(array); 
 
  
  
/*
run:
  
[ 1, 3, 5, 7, 9, 11 ]

*/

 

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