Question

How to print the distinct elements of a list in Kotlin

Answer 1

fun main() {
    val list = listOf(3, 5, 9, 1, 7, 8, 1, 9, 0, 3, 9)

    val uniqueElements = list.filter { item ->
        list.indexOf(item) == list.lastIndexOf(item)
    }

    println(uniqueElements)
}


 
  
/*
run:
  
[5, 7, 8, 0]

*/

 

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