How to remove the letters from word1 if they do not exist in word2 with Node.js

3 Answers

0 votes
// utils.js
function removeNonCommonLetters(word1, word2) {
  let result = '';

  for (let char of word1) {
    if (word2.includes(char)) {
      result += char;
    }
  }

  return result;
}

// You can export the function if you want to use it as a module
module.exports = removeNonCommonLetters;

// index.js
const word1 = "forest";
const word2 = "tor";

const result = removeNonCommonLetters(word1, word2);

console.log(result);



/*
run:

ort

*/

 



answered Jul 10 by avibootz
0 votes
// utils.js
function removeNonCommonLetters(word1, word2) {
  const word2Set = new Set(word2);
     
  return word1
        .split('')
        .filter(char => word2Set.has(char))
        .join('');
}

// You can export the function if you want to use it as a module
module.exports = removeNonCommonLetters;

// index.js
const word1 = "forest";
const word2 = "tor";

const result = removeNonCommonLetters(word1, word2);

console.log(result);



/*
run:

ort

*/

 



answered Jul 10 by avibootz
0 votes
// utils.js
const removeNonCommonLetters = (word1, word2) => 
    [...word1].filter(char => word2.includes(char)).join('');

// You can export the function if you want to use it as a module
module.exports = removeNonCommonLetters;

// index.js
const word1 = "forest";
const word2 = "tor";

const result = removeNonCommonLetters(word1, word2);

console.log(result);



/*
run:

ort

*/

 



answered Jul 10 by avibootz
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