Question

How to check if any value in a one-dimensional array a is larger than x using std::any_of in C++

Answer 1

#include <iostream>
#include <algorithm> // For std::any_of

bool isAnyValueLargerThanX(const int* arr, int size, int x) {
    return std::any_of(arr, arr + size, [x](int value) { return value > x; });
}

int main() {
    int arr[] = {1, 2, 3, 4, 5, 6};
    int x = 4;
    int size = sizeof(arr) / sizeof(arr[0]);

    if (isAnyValueLargerThanX(arr, size, x)) {
        std::cout << "There is a value larger than " << x << " in the array.\n";
    } else {
        std::cout << "No value is larger than " << x << " in the array.\n";
    }
}



/*
run:

There is a value larger than 4 in the array.

*/

 

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