Question

How to sort each column of a matrix with strings in JavaScript

Answer 1

function sortColumns(matrix) {
    let rows = matrix.length;
    let cols = matrix[0].length;

    for (let col = 0; col < cols; col++) {
        // Extract column into an array
        let column = [];
        for (let row = 0; row < rows; row++) {
            column.push(matrix[row][col]);
        }

        // Sort the column
        column.sort();

        // Place sorted values back into the matrix
        for (let row = 0; row < rows; row++) {
            matrix[row][col] = column[row];
        }
    }
}

function printMatrix(matrix) {
    matrix.forEach(row => console.log(row.join(" ")));
}

let matrix = [
    ["ccc", "zzzz", "yyyyyy"],
    ["eeee", "aaa", "ffff"],
    ["uu", "hhh", "uuu"],
    ["bbb", "gg", "x"]
];

console.log("Original Matrix:");
printMatrix(matrix);

sortColumns(matrix);

console.log("\nSorted Matrix:");
printMatrix(matrix);

  
  
/*
run:
      
Original Matrix:
ccc zzzz yyyyyy
eeee aaa ffff
uu hhh uuu
bbb gg x

Sorted Matrix:
bbb aaa ffff
ccc gg uuu
eeee hhh x
uu zzzz yyyyyy

*/
 

 

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