Question

How to get separate digits of an int number in Java

Answer 1

import java.util.Arrays;

public class MyClass {
    public static void main(String args[]) {
        int n = 923047;
         
        String sn = String.valueOf(n);
         
        char[] digits = sn.toCharArray();
         
        System.out.println(Arrays.toString(digits));
    }
}




/*
run:

[9, 2, 3, 0, 4, 7]

*/

 

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Answer 2

public class MyClass {
    public static void main(String args[]) {
        int n = 923047;
         
        String sn = String.valueOf(n);

        char[] digits = sn.toCharArray();
          
        for (int i = 0; i < digits.length; i++)
             System.out.println(digits[i]);
    }
}




/*
run:

9
2
3
0
4
7

*/

 

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Answer 3

public class MyClass {
    public static void main(String args[]) {
        int n = 9801725;
 
        while (n > 0) {
            System.out.println(n % 10);
            n = n / 10;
        }
    }
}




/*
run:

5
2
7
1
0
8
9

*/

 

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Answer 4

import java.util.LinkedList; 

public class MyClass {
    public static void main(String args[]) {
        int n = 9801725;
 
        LinkedList<Integer> ll = new LinkedList<Integer>();
        
        while (n > 0) {
            ll.push(n % 10 );
            n = n / 10;
        }
 
        while (!ll.isEmpty()) {
            System.out.println(ll.pop());
        }
    }
}




/*
run:

9
8
0
1
7
2
5

*/

 

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