Question

How to find repeated rows of a matrix in JavaScript

Answer 1

function rowToString(row) {
    return row.join(",");
}

function findRepeatedRows(matrix) {
    let rowCount = {};

    for (let row of matrix) {
        let pattern = rowToString(row);
        rowCount[pattern] = (rowCount[pattern] || 0) + 1;
    }

    console.log("Repeated Rows:");
    for (let [pattern, count] of Object.entries(rowCount)) {
        if (count > 1) {
            console.log(`Row: [${pattern}] - Repeated ${count} times`);
        }
    }
}

const matrix = [
    [1, 2, 3],
    [4, 5, 6],
    [1, 2, 3],
    [7, 8, 9],
    [4, 5, 6],
    [0, 1, 2],
    [4, 5, 6]
];

findRepeatedRows(matrix);




/*
run:

Repeated Rows:
Row: [1,2,3] - Repeated 2 times
Row: [4,5,6] - Repeated 3 times

*/

 

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