Question

How to check if a matrix rows contain numbers without repetition in Swift

Answer 1

import Foundation

func rowsHaveUniqueNumbers(matrix: [[Int]]) -> Bool {
    for row in matrix {
        let uniqueNumbers = Set(row)
        if uniqueNumbers.count != row.count {
            return false // Row contains duplicates
        }
    }
    return true // All rows have unique numbers
}

// Example usage
let matrix1 = [
    [1, 2, 3],
    [4, 5, 6],
    [7, 8, 9]
]

let matrix2 = [
    [1, 2, 1], // 1, 1
    [4, 5, 6],
    [7, 8, 9]
]

print(rowsHaveUniqueNumbers(matrix: matrix1)) 
print(rowsHaveUniqueNumbers(matrix: matrix2)) 



/*
run:

true
false

*/

 

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