Question

How to get the base 10 logarithm of a double value in Java

Answer 1

class Program {
    public static void main(String[] args) {
        System.out.println("Math.log10(0) = " + Math.log10(0));
        System.out.println("Math.log10(1) = " + Math.log10(1));
        System.out.println("Math.log10(-1) = " + Math.log10(-1));
        System.out.println("Math.log10(2) = " + Math.log10(2));
        System.out.println("Math.log10(-2) = " + Math.log10(-2));
        System.out.println("Math.log10(5) = " + Math.log10(5));
        System.out.println("Math.log10(10) = " + Math.log10(10));
        System.out.println("Math.log10(100) = " + Math.log10(100));
        System.out.println("Math.log10(100000) = " + Math.log10(100000));
        System.out.println("Math.log10(125) = " + Math.log10(125));
        System.out.println("Math.log10(125)/Math.log10(5) = " + Math.log10(125)/Math.log10(5));
    }
}




/*
run:

Math.log10(0) = -Infinity
Math.log10(1) = 0.0
Math.log10(-1) = NaN
Math.log10(2) = 0.3010299956639812
Math.log10(-2) = NaN
Math.log10(5) = 0.6989700043360189
Math.log10(10) = 1.0
Math.log10(100) = 2.0
Math.log10(100000) = 5.0
Math.log10(125) = 2.0969100130080562
Math.log10(125)/Math.log10(5) = 2.9999999999999996

*/

 

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