Question

What is the double value that is the closer to e, the base of the natural logarithms in Java

Answer 1

package javaapplication1;

public class JavaApplication1 {
 
    public static void main(String[] args) {
        
        System.out.println(Math.E); 
    }
}
 
/*
run:

2.718281828459045
 
*/

 

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