What is the double value that is the closer to e, the base of the natural logarithms in Java

1 Answer

0 votes
package javaapplication1;

public class JavaApplication1 {
 
    public static void main(String[] args) {
        
        System.out.println(Math.E); 
    }
}
 
/*
run:

2.718281828459045
 
*/

 



answered Sep 9, 2016 by avibootz
...