How to get the sine of a number (double) in Java

1 Answer

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package javaapplication1;

public class JavaApplication1 {
 
    public static void main(String[] args) {
        
        System.out.println("Math.sin(1) = " + Math.sin(1));
        System.out.println("Math.sin(0) = " + Math.sin(0));
        System.out.println("Math.sin(-1) = " + Math.sin(-1));
        System.out.println("Math.sin(-0) = " + Math.sin(-0));
        System.out.println("Math.sin(Math.PI / 2) = " + Math.sin(Math.PI / 2));
        System.out.println("Math.sin(Math.PI / 6) = " + Math.sin(Math.PI / 6));
        System.out.println("Math.sin(Math.PI / 180) = " + Math.sin(Math.PI / 180));
        System.out.println("Math.sin(-2 * Math.PI / 4) = " + Math.sin(-2 * Math.PI / 4));
        System.out.println("Math.sin(45) = " + Math.sin(45));
    }
}
 
/*
run:

Math.sin(1) = 0.8414709848078965
Math.sin(0) = 0.0
Math.sin(-1) = -0.8414709848078965
Math.sin(-0) = 0.0
Math.sin(Math.PI / 2) = 1.0
Math.sin(Math.PI / 6) = 0.49999999999999994
Math.sin(Math.PI / 180) = 0.01745240643728351
Math.sin(-2 * Math.PI / 4) = -1.0
Math.sin(45) = 0.8509035245341184
 
*/

 



answered Sep 8, 2016 by avibootz

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