How to use ceil() to get the smallest integer that is greater than or equal to the argument in Java

1 Answer

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package javaapplication1;

public class JavaApplication1 {
 
    public static void main(String[] args) {
        
        double d1 = -3.678;
        double d2 = -3.578;
        double d3 = -3.478;
        double d4 = -3.998;
        double d5 = 3.998;
        double d6 = 3.567;
        double d7 = 3.234;
        float f1 = -120;    
        float f2 = 31;    

        System.out.println(Math.ceil(d1));
        System.out.println(Math.ceil(d2));
        System.out.println(Math.ceil(d3));
        System.out.println(Math.ceil(d4));
        System.out.println(Math.ceil(d5));
        System.out.println(Math.ceil(d6));
        System.out.println(Math.ceil(d7));
        System.out.println(Math.ceil(f1));  
        System.out.println(Math.ceil(f2));  
    }
}
 
/*
run:

-3.0
-3.0
-3.0
-3.0
4.0
4.0
4.0
-120.0
31.0
 
*/

 



answered Sep 7, 2016 by avibootz
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