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How to print all command line arguments except the program name in C++

1 Answer

0 votes
#include <iostream>

int main(int argc, char * argv[])
{
	for (int i = 1; i < argc; i++) {
		std::cout << (1 == i ? "" : " ") << argv[i];
	}
	
    std::cout <<std::endl;
}


/*
run:

abc 123 F22

*/

 



answered May 8, 2025 by avibootz
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