Question

How to continue outer loop in TypeScript

Answer 1

const a: number[] = [4, 5, 1, 1, 6, 7, 0, 1, 1, 1, 8];
const b: number[] = [9, 1, 2];
        
OUTER:
for (let i in a) {
   for (let j in b) {
      if (a[i] === b[j]) {
         continue OUTER;
      }
   }
   console.log(a[i]);
}
 
 
 
/*
run:
 
4
5
6
7
0
8
 
*/
 

 

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