Question

How to declare and use an array of 3 pointers to int in C

Answer 1

#include <stdio.h>

int main(void)
{
    int *arr[3]; // declaration of an array of 3 pointers to int
    int a = 3, b = 6, c = 9;
    
    arr[0] = &a;
    arr[1] = &b;
    arr[2] = &c;
    
    printf("%d\n", *arr[0]); 
    printf("%d\n", *arr[1]); 
    printf("%d\n", *arr[2]); 
        
    return 0;
}

/*
run:
 
3
6
9

*/

 

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