Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,890 questions

51,817 answers

573 users

How to extract the unique integers from a list excluding duplicates in Java

1 Answer

0 votes
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;

public class Main {
    public static List<Integer> getUniqueExcludeDuplicates(List<Integer> lst) {
        HashMap<Integer, Integer> frequency = new HashMap<>(); // To count occurrences of each number
        List<Integer> result = new ArrayList<>();             // To store unique values

        // Count frequencies of each number in the list
        for (int num : lst) {
            frequency.put(num, frequency.getOrDefault(num, 0) + 1);
        }

        // Collect numbers that appear only once
        for (int num : lst) {
            if (frequency.get(num) == 1) {
                result.add(num); // Add to result if it's truly unique
            }
        }

        return result;
    }

    public static void main(String[] args) {
        List<Integer> lst = List.of(1, 2, 3, 5, 8, 3, 1, 1, 0, 6, 5, 7, 3, 1, 4, 9);

        List<Integer> uniqueValues = getUniqueExcludeDuplicates(lst);

        System.out.print("Unique values (excluding duplicates): ");
        for (int num : uniqueValues) {
            System.out.print(num + " ");
        }
        System.out.println();
    }
}

 
 
/*
run:
 
Unique values (excluding duplicates): 2 8 0 6 7 4 9 
 
*/

 



answered Mar 28, 2025 by avibootz
...