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How to extract the unique integers from a vector excluding duplicates in C++

1 Answer

0 votes
#include <iostream>
#include <vector>
#include <unordered_map>

std::vector<int> getUniqueExcludeDuplicates(const std::vector<int>& vec) {
    std::unordered_map<int, int> frequency; // To count occurrences of each number
    std::vector<int> result;               // To store unique values (exclude duplicates)

    // Count frequencies of each number in the vector
    for (int num : vec) {
        frequency[num]++;
    }

    // Collect numbers that appear only once
    for (int num : vec) {
        if (frequency[num] == 1) {
            result.push_back(num); // Add to result if it's truly unique
        }
    }

    return result;
}

int main() {
    std::vector<int> vec = {1, 2, 3, 5, 8, 3, 1, 1, 0, 6, 5, 7, 3, 1, 4, 9};

    // Call the function to exclude duplicates
    std::vector<int> uniqueValues = getUniqueExcludeDuplicates(vec);

    std::cout << "Unique values (excluding duplicates): ";
    for (int num : uniqueValues) {
        std::cout << num << " ";
    }
    std::cout << std::endl;

    return 0;
}

 
 
/*
run:
 
Unique values (excluding duplicates): 2 8 0 6 7 4 9 
 
*/

 

 



answered Mar 28, 2025 by avibootz
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