Question

How to convert string to byte array in C

Answer 1

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

// Function to create a dynamic byte array from a string
unsigned char* createByteArray(const char* str, size_t* len) {
    *len = strlen(str);
    unsigned char* byteArray = (unsigned char*)malloc(*len + 1); // +1 for the null terminator
    if (byteArray == NULL) {
        printf("Memory allocation failed\n");
        return NULL;
    }
    memcpy(byteArray, str, *len + 1);
    
    return byteArray;
}

int main() {
    char* str = "C Programming";
    size_t len = 0;

    // Eventually, it's the same array...
    unsigned char* byteArray = createByteArray(str, &len);
    if (byteArray == NULL) {
        return 1; // Exit the program if allocation failed
    }

    for (size_t i = 0; i < len + 1; i++) {
        printf("%02x ", byteArray[i]);
    }
    printf("\n");

    // Free the allocated memory
    free(byteArray);

    return 0;
}


 
/*
run:
 
43 20 50 72 6f 67 72 61 6d 6d 69 6e 67 00 
 
*/

 

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