Question

How to use csqrt() to compute the complex square root of complex n in C

Answer 1

#include <stdio.h>
#include <complex.h>
 
int main(void)
{
    double complex x = csqrt(-4);
    printf("Square root of -4 is %.1f%+.1fi\n", creal(x), cimag(x));
    
    double complex y = csqrt(9);
    printf("Square root of 9 is %.1f%+.1fi\n", creal(y), cimag(y));
 
    return 0;
}
  
/*
run:
 
Square root of -4 is 0.0+2.0i
Square root of 9 is 3.0+0.0i

*/

 

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