Question

How to convert a string to PascalCase using RegEx in Go

Answer 1

package main

import (
        "fmt"
        "regexp"
        "strings"
        "unicode"
)

func toPascalCase(input string) string {
        // 1. Handle camelCase by inserting spaces
        re := regexp.MustCompile("([a-z])([A-Z])")
        input = re.ReplaceAllString(input, "$1 $2")

        // 2. Replace non-breaking spaces with regular spaces
        input = strings.ReplaceAll(input, "\u00A0", " ")

        // 3. Split into words using spaces and underscores as delimiters
        words := strings.FieldsFunc(strings.ToLower(input), func(r rune) bool {
                return unicode.IsSpace(r) || r == '_'
        })

        var result string
        for _, word := range words {
                if len(word) > 0 {
                        // 4. Capitalize the first letter of each word
                        runes := []rune(word)
                        runes[0] = unicode.ToUpper(runes[0])
                        result += string(runes)
                }
        }
        return result
}

func main() {
        fmt.Println(toPascalCase("get file content"))
        fmt.Println(toPascalCase("get_file_content"))
        fmt.Println(toPascalCase("get______file___content"))
        fmt.Println(toPascalCase("get______file____\u00A0 content"))
        fmt.Println(toPascalCase("GET FILE CONTENT"))
        fmt.Println(toPascalCase("get\u00A0 \u00A0 file\u00A0 \u00A0 \u00A0 content"))
        fmt.Println(toPascalCase("getFileContent"))
        fmt.Println(toPascalCase("  get file content")) 
        fmt.Println(toPascalCase("get file content  ")) 
}



/*
run:

GetFileContent
GetFileContent
GetFileContent
GetFileContent
GetFileContent
GetFileContent
GetFileContent
GetFileContent
GetFileContent

*/

 

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