Question

How to sum the digit of a factorial of a number in Go

Answer 1

package main

import (
    "fmt"
)

func sumDigits(num int) int {
    sum := 0
    
    for num != 0 {
        sum += num % 10
        num /= 10
    }
    
    return sum
}

func factorial(n int) int {
    if n == 1 || n == 0 {
        return 1
    }
    return n * factorial(n-1)
}

func main() {
    number := 9
    result := factorial(number)

    fmt.Println("factorial =", result)
    fmt.Println("sum digits =", sumDigits(result))
}


/*
run:

factorial = 362880
sum digits = 27

*/

 

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