Question

How to bitwise inverse the bits of a number in Kotlin

Answer 1

fun main() {
    val number = 153

    // Print the number in binary with leading zeros to make it 32 bits
    println(number.toUInt().toString(2).padStart(32, '0'))
    println(number)

    // Invert the number and print it in binary with leading zeros to make it 32 bits
    val invertedNumber = number.inv()
    
    println(invertedNumber.toUInt().toString(2).padStart(32, '0'))
    println(invertedNumber)
}

  
   
/*
run:
 
00000000000000000000000010011001
153
11111111111111111111111101100110
-154
 
*/

 

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